Fat fingers?
If Vin is 52 and Vout is 25V then the duty cycle is Vout/Vin or 48%
The average LED current is 1A the peak is 1.15, and the valley is .85A
That means during the ON time the current increases by 300mA
The inductor value is 47uH
So what is the ON time for a 300MA increase in current in a 47uH inductor with 27 volts across it?
V=L di/dt 27= 47e-6 .3/dt dt is 522 nsec
So I get an on time of 522 nsec ( 48% DC) so the off time is a little bit longer at 565 nsec
The total period is 1087nsec which is a frequency of 920khz.